0

Guest

Courses New

the differential equation of circles passing through the origin and having the centres on the x axis is

the differential equation of circles passing through the origin and having the centres on the x axis is

Grade:12

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

Equation of circle is (x-a)*(x-a) + y^2 = a^2

differentiate once to eliminate constant a

Regards
Vikas TU
14149 Points
4 years ago
Dear student 
x^2 = y^2 +2xydy/dx 
Genera equation of all such circles is 
x^2 + y^2 +2gx = 0 
2x +2ydy/dx +2g = 0 
Desired equation is 
x^2 + y^2 +(-2x-2ydy/dx)x = 0 
So y^2 = x^2 +2xydy/dx 
Hope this helps 
Good Luck

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More