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Grade: 12
        
the differential equation of circles passing through the origin and having the centres on the x axis is
6 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
8367 Points
							Dear student

Equation of circle is (x-a)*(x-a) + y^2 = a^2

differentiate once to eliminate constant a

Regards
6 months ago
Vikas TU
11680 Points
							
Dear student 
x^2 = y^2 +2xydy/dx 
Genera equation of all such circles is 
x^2 + y^2 +2gx = 0 
2x +2ydy/dx +2g = 0 
Desired equation is 
x^2 + y^2 +(-2x-2ydy/dx)x = 0 
So y^2 = x^2 +2xydy/dx 
Hope this helps 
Good Luck
6 months ago
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