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the differential equation of circles passing through the origin and having the centres on the x axis is
Dear studentEquation of circle is (x-a)*(x-a) + y^2 = a^2differentiate once to eliminate constant aRegards
Dear student x^2 = y^2 +2xydy/dx Genera equation of all such circles is x^2 + y^2 +2gx = 0 2x +2ydy/dx +2g = 0 Desired equation is x^2 + y^2 +(-2x-2ydy/dx)x = 0 So y^2 = x^2 +2xydy/dx Hope this helps Good Luck
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