Grade 12Differential Calculus
the differential equation of circles passing through the origin and having the centres on the x axis is
the differential equation of circles passing through the origin and having the centres on the x axis is
2 Answers
Saurabh Koranglekar
Approved Tutor Answer6 Years agoDear student
Equation of circle is (x-a)*(x-a) + y^2 = a^2
differentiate once to eliminate constant a
Regards
Equation of circle is (x-a)*(x-a) + y^2 = a^2
differentiate once to eliminate constant a
Regards
Vikas TU
Approved Tutor Answer6 Years agoDear student
x^2 = y^2 +2xydy/dx
Genera equation of all such circles is
x^2 + y^2 +2gx = 0
2x +2ydy/dx +2g = 0
Desired equation is
x^2 + y^2 +(-2x-2ydy/dx)x = 0
So y^2 = x^2 +2xydy/dx
Hope this helps
Good Luck
x^2 = y^2 +2xydy/dx
Genera equation of all such circles is
x^2 + y^2 +2gx = 0
2x +2ydy/dx +2g = 0
Desired equation is
x^2 + y^2 +(-2x-2ydy/dx)x = 0
So y^2 = x^2 +2xydy/dx
Hope this helps
Good Luck
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