Differential Calculus
the derivative of sec-1[1/2x2-1] with respect to root[1-x2] at x=1/2 is equal to?
the derivative of sec-1[1/2x2-1] with respect to root[1-x2] at x=1/2 is equal to?
1 Answer
noogler
Put x=coso in sec-1[1/2x2-1] then u get 2o put again o=cos-1x then diff with respect to x......1
similarly put x=coso in [1-x2]½ u get sino put again o=cos-1x then diff with respecttox...........2
der of 1w.r.t 2 is 2d(cos-1x)/d(sin[cos-1x])=2/(1/2)=4
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