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The derivation of f(tan x) w.r.t g(sec x) at x= pi/4 where f`(1)=2 and g`(sqrt2)=4 is The derivation of f(tan x) w.r.t g(sec x) at x= pi/4 where f`(1)=2 and g`(sqrt2)=4 is
[d(f(tanx))/dx] / [d(g(secx))/dx]=[(f '(tan(x))*sec2x] / [(g '(secx)) secx*tanx]put x=pi/4=[(f '(1)*(v2)^2] / [(g'(v2))*v2*1]=(2*2) / (4*v2)=1/v2Thanks and Regards,Vinod Kumar,askIITians faculty,IIT- Delhi
Thanks and Regards,Vinod Kumar,askIITians faculty,
IIT- Delhi
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