The coordinate of the point on y^2=8x which is closest from x^2 + (y+6)^2 =1 is ?
Arpit Dhankar , 10 Years ago
Grade 12th pass
3 Answers
Jitender Singh
Last Activity: 10 Years ago
Ans: Hello Student, Please find answer to your question below
Minimum distance b/w any two curves lie along common normal So if we find the coordinate where common normal touches the parabola, then thats coordinate will be closest to circle Equation normal to parabola: where m is slope of normal So this common normal will pass through the centre of circle also Centre (0, -6) So, m = 1 is one solution which is also clear from the figure. Put this in parabola y = -4, 12 x = 2, 18 (2, -4) is the closest which is clear from the diagram.
Arpit Dhankar
Last Activity: 10 Years ago
thank you sir
Arpit Dhankar
Last Activity: 10 Years ago
thank you sir
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