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TANGENTS AND NORMALS find the points on the curve y=3x^2 + 4 at which the tangent is perpendicular to the line whose slope is -1/6

TANGENTS AND NORMALS
find the points on the curve y=3x^2 + 4 at which the tangent is perpendicular to the line whose slope is -1/6

Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
6 years ago
Ans:
Hello Student,
Please find answer to your question below

Since tangent is perpendicular to line with slope (-1/6). Let tangent slope be m.
m(\frac{-1}{6}) = -1
m = 6
y = 3x^2 + 4
y' = 6x
6x = 6
x = 1
Put in curve
y = 7



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