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Grade 12Differential Calculus

TANGENTS AND NORMALS
find the points on the curve y=3x^2 + 4 at which the tangent is perpendicular to the line whose slope is -1/6

Profile image of taniska
11 Years agoGrade 12
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1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:
Hello Student,
Please find answer to your question below

Since tangent is perpendicular to line with slope (-1/6). Let tangent slope be m.
m(\frac{-1}{6}) = -1
m = 6
y = 3x^2 + 4
y' = 6x
6x = 6
x = 1
Put in curve
y = 7


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