+91-87964 74404
FlagBACK
Question icon
Grade 12Differential Calculus

tangents and normals
find the equations of all lines of slope zero and that are tangent to the curve y=1 / (x^2 – 2x + 3)

Profile image of taniska
11 Years agoGrade 12
Answers icon

1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:
Hello Student,
Please find answer to your question below

y = \frac{1}{x^2 - 2x + 3}
Slope of tangent: y’ = 0
y' = \frac{-(2x-2)}{(x^2 - 2x + 3)^2}
\frac{-(2x-2)}{(x^2 - 2x + 3)^2} = 0
\Rightarrow x = 1
Put in equation
y = \frac{1}{1^2 - 2.1 + 3}
y = \frac{1}{2}
this is the equation of tangent

Other Related Questions on differential calculus

question mark
the diameter of a roller is 84 cm and its length is 120 cm. it takes 500 complete revolution to  move once over to level a playground. find the area of the playground in square m?
differential calculus
1 Answer Available

Last Activity: 3 Years ago

question mark
Find dy/DX when y=x^sinx+sin-1√x.
 
Please give me the solution of this problem. 
differential calculus
1 Answer Available

Last Activity: 4 Years ago

question mark
If domain of f(x) is [-1, 2], then find the domain of f([x]-x^2+4), where [ ]denotes greatest integer function.
differential calculus
1 Answer Available

Last Activity: 4 Years ago

question mark
Solve the differential equation y’’+2ty’-4y=1, y(0)=y’(0)=0.
differential calculus
1 Answer Available

Last Activity: 4 Years ago

question mark
Example 20. (i) In a AABC, find the maxima and minima of u = sin A sin B sin C
where A + B + C = T
(ii) In a plane triangle ABC, find the maximum value of cosA cosB cosC.
differential calculus
1 Answer Available

Last Activity: 4 Years ago