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tangents and normals
find the equation of the tangent line to the curve y=x^2 – 2x + 7 which is perpendicular to the line 5y – 15x =13

taniska , 11 Years ago

Grade 12

1 Answers

Jitender Singh

Ans:
Hello Student,
Please find answer to your question below

$y = x^2 - 2x + 7$
Slope of tangent: y’ = -1/3
$y' = 2x - 2$
$2x - 2 = \frac{-1}{3}$
$x = \frac{5}{6}$
$y = (\frac{5}{6})^2 - 2(\frac{5}{6}) + 7$
$y = \frac{25}{36} - \frac{60}{36} + 7$
$y = - \frac{35}{36} + 7 = \frac{217}{36}$
Equation:
$(y - \frac{217}{36}) = \frac{-1}{3}(x-\frac{5}{6})$

Last Activity: 11 Years ago

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