Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

tangents and normals find the equation of a normal to the curve y=x log e x which is parallel to the line 2x – 2y + 3 = 0

tangents and normals
find the equation of a normal to the curve y=x loge x which is parallel to the line 2x – 2y + 3 = 0 

Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
7 years ago
Ans:
Hello Student,
Please find answer to your question below

y = xlnx
Slope of normal: -1/y’ = 1
y’ = -1
y' = lnx + 1
y' = lnx + 1 = -1
lnx = -2
x = \frac{1}{e^2}
y = \frac{-2}{e^2}
Equation:

(y + \frac{2}{e^2}) = (x - \frac{1}{e^2})

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free