Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

TANGENTS AND NORMALS at what points on the circle x^2 + y^2 – 2x – 4y + 1 = 0 the tangent is parallel to x axis

TANGENTS AND NORMALS
at what points on the circle x^2 + y^2 – 2x – 4y + 1 = 0 the tangent is parallel to x axis 
 

Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
6 years ago
Ans:
Hello Student,
Please find answer to your question below

Slope = 0
x^2 + y^2 - 2x - 4y - 1 = 0
2x + 2yy' - 2 - 4y' = 0
y’ = 0
2x - 2 = 0
x = 1
Put in curve:
1 + y^2 - 2 - 4y - 1 = 0
y^2 -4y - 2 = 0
y = \frac{4\pm \sqrt{24}}{2}
y = \frac{4\pm 2\sqrt{6}}{2}
y = 2\pm \sqrt{6}

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More