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Grade: 10

                        

Sum of the digits of the number (10 4n2+8 +1) 2 , where n is a positive integer is ?

4 years ago

Answers : (1)

Sourabh Singh
IIT Patna
askIITians Faculty
2104 Points
							Hii

Be it any number just calculate the total number of zeros that will precede the unit digit in the number

eg 101*101 = 10201
1001 *1001 =1002001
10001*10001 = 100020001

Hence in any case the sum of digigts is always going to be 4
4 years ago
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