Differential Calculus> Square root of x+Under square root of x.+...

Square root of x+Under square root of x.+ under square root of x and so on = square root of x*under square root of x and do on then value of x is

Varshitha , 7 Years ago

Grade 9

1 Answers

Vikas TU

Last Activity: 7 Years ago

Dear Student,

√(x+√x+….. = √(x.√x…..= p

So, from the first one we get

P^2= x + p

From the second one

P^2= x.p

So, x= P

Putting value we get

P^2 = 2p

So, the value of P is 0 or 2.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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Differential Calculus> Square root of x+Under square root of x.+...

Square root of x+Under square root of x.+ under square root of x and so on = square root of x*under square root of x and do on then value of x is

Varshitha , 7 Years ago

Vikas TU

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