Solvex^2d^2y/dx^2+xdy/DX+y=0Prove that y= acid(logx)+bsin(logx)

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Arun · Answer

Dear Rajat If you take the later part true you can provw the former part. i.e. Take y = a cos(logx) + b sin(log x) Now prove x² d²y/dx² + xdy/dx + y = 0

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Solvex^2d^2y/dx^2+xdy/DX+y=0Prove that y= acid(logx)+bsin(logx)

Solvex^2d^2y/dx^2+xdy/DX+y=0Prove that y= acid(logx)+bsin(logx)

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Solvex^2d^2y/dx^2+xdy/DX+y=0Prove that y= acid(logx)+bsin(logx)

Solvex^2d^2y/dx^2+xdy/DX+y=0Prove that y= acid(logx)+bsin(logx)

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