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Grade 12th passIntegral Calculus

Solve the initial value problem.
xy' = y2 + y , y(4) = 2

Profile image of Bharat Bhusan Samal
8 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
8 Years ago
Dear Bharat
 
dy/dx = y² +y /x
 
dy/y2 +y = dx/x
 
dy/y(y+1) = dx/x
 
(1/y - 1/y+1) dy = dx/x
 
On integrating
 
ln y - ln (y+1) = ln x + ln c
 
ln [y/y+1] = ln cx
 
Now
 
y /(y+1) = cx
 
Now
 
Put x = 4, y = 2
 
2/3 = 4c
 
c = 1/6
 
Hence
 
y/(y+1) = x/6