solve of the following differential equation x ((e^y) + 4) dx + (e^(x+y)) dy = 0

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Aditya Gupta · Answer

put z=e^y+4 or dz= e^ydy so eqn becomes xzdx + e^xdz=0 or xe^-x dx= – dz/z now you cn integrate n solve

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solve of the following differential equation x ((e^y) + 4) dx + (e^(x+y)) dy = 0

solve of the following differential equation
x ((e^y) + 4) dx + (e^(x+y)) dy = 0

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solve of the following differential equation x ((e^y) + 4) dx + (e^(x+y)) dy = 0

solve of the following differential equationx ((e^y) + 4) dx + (e^(x+y)) dy = 0

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solve of the following differential equation
x ((e^y) + 4) dx + (e^(x+y)) dy = 0