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Sir please explain fully ….......it's answer is (b) please sir ….please ....

milind , 11 Years ago
Grade 12
anser 1 Answers
Jitender Singh

Hello student,
Please find answer to your question
L = x.logx.log^{2}x..........log^{n-1}x.log^{n}x.\frac{dy}{dx}
L = x.logx.log^{2}x..........log^{n-1}x.log^{n}x.\frac{1}{log^{n-1}x}..........\frac{1}{log^{2}x}.\frac{1}{logx}.\frac{1}{x}
L = log^{n}x
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty
Last Activity: 11 Years ago
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