Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Show that the line x/a+y/b=1, touches the curve y=b×e^-x/a at the point where the curve intersect the axis of y.
The curve cuts the y-axis where x=0, so at the point P(0,b). The tangent to the curve has slope dy/dx=-(b/a)e^(-x/a) =-(b/a) at P. The equation of this tangent is (y-b)=(-b/a)x which , dividing by b gives y/b - 1 = (-1/a)x giving x/a+y/b=1 and this is the given line. So the result has been shown.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -