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`        show that among all positive numbers x and y with x^2 + y^2 = r^2, the sum of x+y is largest when x=y=r/(sqrt 2)`
5 years ago

Arun Kumar
IIT Delhi
256 Points
```							Hi$\\x^2 + y^2 = r^2 \\x+y=s \\=>{ds \over dx}=0=1+{dy \over dx} \\2x+2y {dy \over dx}=0 \\=>{dy \over dx}={-x \over y} \\=>{-x \over y}=-1 \\=>y=x \\=>2x^2=r^2 \\=>x=r/ \sqrt2$Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
```
5 years ago
Rinkoo Gupta
80 Points
```							S=x+y=x+v(r2-x2)

Ds/dx=1+(-2x)/2v(r2-x2)
put ds/sx=0 , we get

1-x/v(r2-x2)=0

ð X=r/v2

ð D2s/dx2=0- { v(r2-x2).1+x2/v(r2-x2)}

ð D2/dx2=-r2/v(r2-x2)

Pur x=r/v2, we getY=v(r2-x2)=v(r2-r2/2=vr2/2=r/v2

So x=y=r/v2Thanks & regardsRinkoo GuptaaskIITians faculty
```
5 years ago
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### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions