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Grade 12Differential Calculus

see attchment …..and tell the method which is used in solution

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milind

11 Years agoGrade 12

1 Answer

Jitender Singh

11 Years ago

Ans:

Hello student,
Please find the answer to your question below

$L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+............+[\frac{3}{4}+\frac{99}{100}]$
$[t] = 0, 0 <=t < 1$
$[t] = 1, 1 <= t < 2$
Now looking at the problem in hand
$[\frac{3}{4}+\frac{x}{100}] = 0, 0 <= x < 25$
$[\frac{3}{4}+\frac{x}{100}] = 0, 25 <= x < 99$
There are total 100 term in L out of which 25 terms are zero. Rest all the terms are equal to 1. So the sum is 75.

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