0

Guest

Courses New

See attachment sir please explain this question …...I’ll be very great full

See attachment sir please explain this question …...I’ll be very great full 

Question Image
Grade:12

2 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
9 years ago
Hello Student,

\\y=log^n x \\=>{dy \over dx}={1 \over log^{n-1}x*log^{n-2}x......logx} \\=>log^{n-1}x*log^{n-2}x......logx*{dy \over dx}=1 \\=>log^nx* log^{n-1}x*log^{n-2}x......logx*{dy \over dx}=log^nx
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
milind
23 Points
9 years ago
Differential of log ^n x is 

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More