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see attachment ...and please tell the method which is used in solution please reply anyone ….i heard lot about this website

see attachment ...and please tell the method which is used in solution please reply anyone ….i heard lot about this website 

Question Image
Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
7 years ago
Ans:

Hello student,
Please find the answer to your question below

?L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+............+[\frac{3}{4}+\frac{99}{100}]L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+..........+[\frac{3}{4}+\frac{99}{100}]
[t] = 0, 0 <=t < 1
[t] = 1, 1 <= t < 2
Now looking at the problem in hand
[\frac{3}{4}+\frac{x}{100}] = 0, 0 <= x < 25
[\frac{3}{4}+\frac{x}{100}] = 0, 25 <= x < 99
There are total 100 term in L out of which 25 terms are zero. Rest all the terms are equal to 1. So the sum is 75.

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