# see attachment and explain with solution

Grade:12

## 1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
8 years ago
Ans: 6 km/hr
Let ‘x’ be the distance of the man from the lamp post at any moment & ‘l’ be the length of the shadow formed.
Distance of man from lamp post = x km
Distance of shadow from lamp post = (x+l) km
Height of the man = 1.5 km
Height of lamp post = 4.5 km
Using similar triangles, we have
$\frac{x+ l}{l} = \frac{4.5}{1.5}$
$\frac{x+ l}{l} = 3$
$x = 2l$
Differentiate on both sides, we have
$\frac{dl}{dt} = \frac{1}{2}.\frac{dx}{dt}$
$\frac{dl}{dt} = \frac{1}{2}.4 = 2 (\frac{km}{hr})$
Velocity of shadow:
$\frac{d(x+l)}{dt} = \frac{dx}{dt} + \frac{dl}{dt} = 4 + 2 = 6(\frac{km}{hr})$
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

## ASK QUESTION

Get your questions answered by the expert for free