see attachment and explain it

 see attachment and explain it

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1 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
8 years ago
If you function is f=root(1-e^{-x^2})
Then its continuous around 0.
But its not differentiable around zero because the graph of function isn't smooth around zero.
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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