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Range of f(x)=[1+sinx]+[cosx-1]+[tan -1 x] x belongs to (0,2pi)

Range of f(x)=[1+sinx]+[cosx-1]+[tan-1x] x belongs to (0,2pi)

 

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1 Answers

Drake
277 Points
7 years ago
In my opinion [-3,6)

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