Aditya Gupta
Last Activity: 5 Years ago
hello sanjay, both the above answers are wrong. the correct answer would be option 2 f(10)= 10.
in fact, f(x)= 10 for all x in [1, 10].
reason: note that f is defined from [1, 10] to Q. but Q stands for rational numbers. now, lets assume there exists an x= m in [1, 10] for which f(m) is not equal to 10. then, by intermediate value theorem it would mean that f takes all the possible values between f(m) and 10 as f is continuous. however, given any two distinct real numbers, there always exist infinitely many rational as well as irrational numbers between them. so, it means that since f(m) and 10 are distinct, f is bound to have attained an irrational value lying in between f(m) and 10. but f could have only attained rational values, hence by contradiction our initial claim that there exists an x= m in [1, 10] for which f(m) is not equal to 10 was FALSE. so, f(x)= 10.
kindly approve :)