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Grade 12Differential Calculus

Question 1
If f(x) is a continuous and differentiable function and f(1/n) = 0, for all n ≥ 1 and n belongs to I, then
Options
1. f(x) = 0, x E(0, 1]
2. f(0) = 0, f '(0) = 0
3. f '(x) = 0 = f (x), xE (0, 1]
4. f(0) = 0 and f '(0) need not to be zero

Profile image of shashank raom
11 Years agoGrade 12
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer0 Years ago

To tackle the question regarding the function \( f(x) \) that is continuous and differentiable, and satisfies \( f(1/n) = 0 \) for all \( n \geq 1 \), we need to analyze the implications of this condition. Let's break down the options provided and see which one aligns with the properties of \( f(x) \).

Understanding the Condition

The condition \( f(1/n) = 0 \) implies that as \( n \) increases, \( 1/n \) approaches 0. Therefore, we can say that \( f(x) \) has infinitely many points converging to 0 where the function value is 0. This suggests that \( f(0) \) must also be 0 due to the continuity of \( f(x) \).

Analyzing the Options

  • Option 1: \( f(x) = 0 \) for \( x \in (0, 1] \)
  • This option suggests that \( f(x) \) is identically zero in the interval \( (0, 1] \). While it is true that \( f(1/n) = 0 \) for all \( n \), this does not necessarily mean that \( f(x) \) must be zero for every \( x \) in that interval. Thus, this option is too strong and cannot be concluded from the given information.

  • Option 2: \( f(0) = 0 \) and \( f'(0) = 0 \)
  • We have established that \( f(0) = 0 \) due to continuity. However, we cannot conclude that \( f'(0) = 0 \) without additional information about the behavior of \( f(x) \) near 0. Therefore, this option is not necessarily true.

  • Option 3: \( f'(x) = 0 \) and \( f''(x) = 0 \) for \( x \in (0, 1] \)
  • This option suggests that the first and second derivatives of \( f(x) \) are zero in the interval \( (0, 1] \). While \( f'(x) = 0 \) would imply that \( f(x) \) is constant, we cannot conclude this from the given condition. Hence, this option is also not valid.

  • Option 4: \( f(0) = 0 \) and \( f'(0) \) need not be zero
  • This option aligns with our earlier analysis. We have established that \( f(0) = 0 \) due to continuity, and it is indeed possible for \( f'(0) \) to be non-zero. This means that while the function touches the x-axis at 0, it can still have a slope at that point. Therefore, this option is the most reasonable conclusion based on the information provided.

Final Thoughts

Given the analysis above, the correct answer is Option 4: \( f(0) = 0 \) and \( f'(0) \) need not be zero. This reflects the continuity of \( f(x) \) at 0 while allowing for the possibility of a non-zero derivative at that point. Understanding these properties of continuous and differentiable functions is crucial in calculus, as they help us analyze the behavior of functions around specific points.