Q)The value of the parameter a,for which the function f(x)=1+ax,a is not equal to zero is the inverse of itself,is a)-2 b)-1 c)1 d)2 PLZ solve it sir

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Vikas TU · Answer

Inverse of f(x) is: y = ax + 1 ax = y – 1 x = (y-1)/a or y(x) = (x-1)/a then, (x-1)/a = (1+ax) solve the quadratic and fin the dicriminant and its range.

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Q)The value of the parameter a,for which the function f(x)=1+ax,a is not equal to zero is the inverse of itself,is a)-2 b)-1 c)1 d)2 PLZ solve it sir

Q)The value of the parameter a,for which the function f(x)=1+ax,a is not equal to zero is the inverse of itself,is
a)-2 b)-1 c)1 d)2
PLZ solve it sir

1 Answers

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Q)The value of the parameter a,for which the function f(x)=1+ax,a is not equal to zero is the inverse of itself,is a)-2 b)-1 c)1 d)2 PLZ solve it sir

Q)The value of the parameter a,for which the function f(x)=1+ax,a is not equal to zero is the inverse of itself,is a)-2 b)-1 c)1 d)2PLZ solve it sir

1 Answers

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Q)The value of the parameter a,for which the function f(x)=1+ax,a is not equal to zero is the inverse of itself,is
a)-2 b)-1 c)1 d)2
PLZ solve it sir