Q.48 see image.................................................
Harsh vijay , 5 Years ago
Grade 12
Algebra> Q.48 see image..............................
1 Answers
Aditya Gupta
Last Activity: 5 Years ago
actually the ans is really big to be writen here. so let me tell u the basic method:
let the center of incircle of ABC be O. then sin(OBC)= (r – 4)/(r+4) where r is the radius of ABC
similarly sin(OAB)= (r – 1)/(r+1) and sin(OCA)= (r – 9)/(r+9)..... note that to prove all these you will need to apply elementary geometry learnt in class 9th.
now, OBC+OAB+OCA= 180/2= 90
hence we have 4 variables: r, OBC, OAB and OCA and four eqns. so eliminate all other variables to solve for r (note that this would be a bit lengthy).
finally you must get r= 11.
kindly approve :)
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