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Q.26 second OR question I need the complete solution. Answer as soon as possible
I have assumed theta as a for the sake of writing dy/da = e^a ( 2 sin a + sin2a) + e^a ( 2 cos a + 2 cos2a) dx/da = e^a ( 2 cosa + cos2a) - e^a ( 2 sin a - 2 sin2a) Hence dy/dx = (sina + sin2a + cos a + cos2a) /(cosa + cos2a - sina - sin2a) = [2 sin (3a/2) cos (a/2) + 2 cos (3a/2) cos (a/2)] / [ 2 cos(3a/2) cos (a/2) - 2 sin (3a/2) cos (a/2)] = [ sin (3a/2) + cos(3a/2) ]/ [ cos(3a/2) - sin (3a/2)] =[ 1 + tan (3a/2) ]/ [1 - tan (3a/2)] = tan (π/4 + 3a/2) Thanks and regards
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