Q.26 second OR questionanswer as soon as possible.
Q.26 second OR question
answer as soon as possible.
Asiya Anas , 5 Years ago
Grade 12
Differential Calculus> Q.26 second OR question answer as soon as...
2 Answers
Arun
Dear student
I have assumed theta as a for the sake of writing
dy/da = e^a ( 2 sin a + sin2a) + e^a ( 2 cos a + 2 cos2a)
dx/da = e^a ( 2 cosa + cos2a) - e^a ( 2 sin a - 2 sin2a)
Hence
dy/dx = (sina + sin2a + cos a + cos2a) /(cosa + cos2a - sina - sin2a)
= Now use sin2a = 2 sina cosa
Arun
dy/da = e^a ( 2 sin a + sin2a) + e^a ( 2 cos a + 2 cos2a)
dx/da = e^a ( 2 cosa + cos2a) - e^a ( 2 sin a - 2 sin2a)
Hence
dy/dx = (sina + sin2a + cos a + cos2a) /(cosa + cos2a - sina - sin2a)
= [2 sin (3a/2) cos (a/2) + 2 cos (3a/2) cos (a/2)] / [ 2 cos(3a/2) cos (a/2) - 2 sin (3a/2) cos (a/2)]
= [ sin (3a/2) + cos(3a/2) ]/ [ cos(3a/2) - sin (3a/2)]
=[ 1 + tan (3a/2) ]/ [1 - tan (3a/2)]
= tan (π/4 + 3a/2)
Hope it helps
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