prove that the tangent to the curve y=(1+3x^2)/(3+x^2) drawn at the point y=1

Question

Arun · Answer

Dear student If we put y = 1 Then 1 = (1+3x²) /(3 +x²) Now 3 + x² = 1 + 3x² 2x² = 2 x = ± 1 Now find dy/dx and then find the equation of tangent

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prove that the tangent to the curve y=(1+3x^2)/(3+x^2) drawn at the point y=1

prove that the tangent to the curve y=(1+3x^2)/(3+x^2) drawn at the point y=1

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prove that the tangent to the curve y=(1+3x^2)/(3+x^2) drawn at the point y=1

prove that the tangent to the curve y=(1+3x^2)/(3+x^2) drawn at the point y=1

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Other Related Questions on Differential Calculus

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