Plz help me out i am helpless...... answer is (2) option that is 0

Dear Student
f(x) = (1-x)^n
f’(x) = -n(1-x)^n-1
f’’(x) = +n(n-1)(1-x)^n-2
And so on
When you put x=0
f(0) = 1
f’(0) = -n
f’’(0) = n(n-1)/2
The pattern as you observe ..The terms are nC0 –nC1 + nC2+...
This the binomial expansion of (1-x)^n when x=1, so the ans is 0
Hope you got it