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Plz do help on these qstns Plz Plz I'm begging.... Thought a lot Didn't got answers yet. Teach me..anyone plz..

Plz do help on these qstns
Plz
Plz
I'm begging....
Thought a lot
Didn't got answers yet. 
Teach me..anyone plz..

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Grade:12

1 Answers

Aditya Gupta
2081 Points
4 years ago
student please ask only 1 doubt per thread as per forum policy.
now, i ll solve 1st one.
y= log[(a – bcosx)/(a+bcosx)]= log(a – bcosx) – log(a+bcosx) (using property of log(y/x)= logy – logx)
diff both sides wrt x and use CHAIN RULE
dy/dx= [d(log(a – bcosx))/d(a – bcosx)]*[d(a – bcosx)/dx] – [d(log(a+bcosx))/d(a+bcosx)]*[d(a+bcosx)/dx]
= bsinx/(a – bcosx) – b( – sinx)/(a+bcosx)
= bsinx*[1/(a – bcosx) + 1/(a+bcosx)]
= 2absinx/(a^2 – b^2cos^2x)
KINDLY APPROVE :))

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