Pls answer.......Find the range of F(x) =3 + 2 sin x
Shrutika Sansaria , 7 Years ago
Grade 11
2 Answers
Arun
Last Activity: 7 Years ago
as we know range of sin x =[ –1, 1]
so the range of f(x) = [3+ 2*( –1), 3+ 2*(1)]
= [1, 5]
hope it helps
Jheel
Last Activity: 7 Years ago
-1 ≤ sinx ≤1Therefore, -2 ≤ sinx ≤ 2 (multiplying by 2 and since 2 is a no. No change will be there in the inequality) Now, Adding 3, we get; -2+3 ≤ 3+2sinx ≤ 2+3Therefore, 1 ≤ 3+2sinx ≤ 5Therefore, range will be [1, 5]
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