Please tell me Q.No.1 & 2 Solution in full detail.Lets start
Please tell me Q.No.1 & 2 Solution in full detail.
Lets start
Ashish , 6 Years ago
Grade 12th pass
Differential Calculus> Please tell me Q.No.1 & 2 Solution in ful...
2 Answers
Arun
Dear student
1.)
6 y^2 y’ = 2ax + 3 x^2
hence at (a,a)
y’ = 5/6
Now tangent
(y – a) = 5/6 (x – a)
now put x = 0 and y = 0 sperately
then you will get answer as 30 and – 30
Vikas TU
Dear student
Q2. Slope of tangent = dy/dx
dy/dx = dy/dt / dx/dt
dx/dt ,
x = t^2+3t-8
dx/dt = 2t +3
dy/dx = dy/dt / dx/dt
dx/dt ,
x = t^2+3t-8
dx/dt = 2t +3
y = 2t^2 -2t-5
dy/dt = 4t-2
dy/dt = 4t-2
dy/dx = d/dt /x/dt
dy/dx = 4t-2/2t+3
Put the point (2,-1)
x = t^2 +3t-8
2 = t^2 +3t-8
t =2 and t= -5
dy/dx = 4t-2/2t+3
Put the point (2,-1)
x = t^2 +3t-8
2 = t^2 +3t-8
t =2 and t= -5
y = 2t^2-2t -5
-1 = 2t^2 -2t-5
t = -1 and 2
-1 = 2t^2 -2t-5
t = -1 and 2
t=2 is common in both part
calculate dy/dx at t = 2
dy/dx = 6/7
calculate dy/dx at t = 2
dy/dx = 6/7
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