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Please tell how they calculate it sir please see attachment

Please tell how they calculate it sir please see attachment 

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Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
9 years ago
Hello student,
Please find answer to your question
L = 5 + n + \frac{n(n-1)}{2!} + ........+\frac{n!}{n!}
L = 4+ 1 + n + \frac{n(n-1)}{2!} + ........+\frac{n!}{n!}
L = 4+ (1 + n + \frac{n(n-1)}{2!} + ........+\frac{n!}{n!})
By binomial theorm,
2^{n} = (1+1)^{n} = 1 + n + \frac{n(n-1)}{2!} + ........+\frac{n!}{n!}
L = 2^{n} + 4

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