Please solve this question number is 5 and 6.hurry up

Q.5.Here we need parametric differentiation , i.e. , dy/dx = (dy/d(theta))/(dx/d(theta)) also we will divide x and y by a because then RHS will be function of theta .a being constant won`t affect differentiation and will get cancelled out when we find dy/dxI am going to use p for thetaSo, 1/a (dy/dp) = cos p1/a (dx/dp) = -sin p + {((1 + tan² p/2))/(2 tan p/2)}the part in {} simplifies to 1/sin pHence 1/a (dx/dp) = cos ²p/sin pSo dy/dx = tan p=> d²y/dx² = sec² p = 2 for p= pi/4