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Grade: 12th pass 
        Please solve the questions number is 16. Hurry up now.
4 months ago

Answers : (1)

Khimraj
1861 Points 
							
According to question
y(dy/dx) = x
ydy = xdx
\intydy = \intxdx
y2/2 = x2/2 +c
y2 – x2 = 2c
putting point (0,-2)
4 = 2c
So equation of curve is
y2 – x2 = 4
y2 – x2 – 4 = 0.
Hope it clears. If you like answer then please approve it.
4 months ago
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