Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Please solve the question in attachment. ... .. ... ..ANS is 1/√e......... .....

Please solve the question in attachment. ... .. ... ..ANS is 1/√e......... ..... 

Question Image
Grade:12th pass

2 Answers

Aditya Gupta
2075 Points
2 years ago
call the limit L.
then logL= lim [{log(1+x)}/x – 1]/x
now use series of log(1+x)= x – x^2/2+O(x^3)
so logL= lim [1 – x/2+O(x^2) – 1]/x
= – ½
so L= e^(–½ )
L=  1/√e
Aditya Gupta
2075 Points
2 years ago
Note above that we could also use l hospital rule, but sometimes the question becomes 10 times easier when we simply use series expansion. I am giving this advice because there are some classic examples in TMH which are impossible to solve using l hospital rule and can only be solved using series expansion! So it is always advisable to remember all the important series expansions

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free