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Grade: 12th pass
        
Please solve the question in attachment. ... .. ... ..ANS is 1/√e......... ..... 
23 days ago

Answers : (2)

Aditya Gupta
713 Points
							
call the limit L.
then logL= lim [{log(1+x)}/x – 1]/x
now use series of log(1+x)= x – x^2/2+O(x^3)
so logL= lim [1 – x/2+O(x^2) – 1]/x
= – ½
so L= e^(–½ )
L=  1/√e
23 days ago
Aditya Gupta
713 Points
							
Note above that we could also use l hospital rule, but sometimes the question becomes 10 times easier when we simply use series expansion. I am giving this advice because there are some classic examples in TMH which are impossible to solve using l hospital rule and can only be solved using series expansion! So it is always advisable to remember all the important series expansions
22 days ago
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