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Please solve the ques in the attachment................................

Please solve the ques in the attachment................................ 

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Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
Dear Pawan
 
lim(x→0) (1cosec2x+2cosec2x+...+ncosec2x)sin2x
= ncosec2xsin2x[(1/n)cosec2x+(2/n)cosec2x+....+1]sin2x
= n[(1/n)cosec2x+(2/n)cosec2x+....+1]sin2x
= n (as r/n ∞→0)(further as n does not tend to ∞, so we dont have (→0)infinite no. of times. so all the terms can be assumed to be zero)
 
Hence option D is correct.

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