Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 12th pass
Please solve question number 54 step by step................................... 
3 months ago

Answers : (1)

Aditya Gupta
1815 Points
obviously lim x tends to 0 sqrt(a+x)= sqrt(a)
so now we have lim x tends to 0 x^3/(bx – sinx)= sqrt(a)
now use series expansion of sinx= x – x^3/3! + O(x^5)
so, we get lim x tends to 0 x^3/(x(b – 1) + x^3/3! – O(x^5))= sqrt(a)
if b – 1 is not equal to zero, then the lim would be 0 as well which means a= 0 too. but then the original limit wont equal 1. so that b – 1 has to be 0. or b= 1.
now, lim becomes lim x tends to 0 x^3/(x^3/3! – O(x^5))= lim x tends to 0 1/(1/3! – 0)= sqrt(a)
or 6= sqrt(a)
or a= 36
kindly approve yar, r u not able to understand and approve even my correct answers?!!
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details