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Please help me with the above attached question thankyou......

Please help me with the above attached question thankyou......

Question Image
Grade:12

2 Answers

Arun
25763 Points
2 years ago
Dear student
 
Take log to the base e and then differentiate, you will get the required result.
 
Hope it helps
Allison
20 Points
2 years ago
X^y = e​​(x-y) = e^x / e^y
X^y  *  e^y = e^x
(xe)^y = e^x
Take log on both sides of above eq
y * log (xe) = x ---(1)
Differentiate both side wrt x
dy/dx * log x. +  ey/xe. =  1
dy/dx. =  1 – y/x
                 Log(xe)
 
            = x-y / x*log (xe)
From question we know x-y = y * log x
    So   dy/dx=         y*log x
                               X* Log(xe)
From (1) y*log(xe)=x so y/x=1/log(ex), substitute this is above eq to get answer
 
 
 
 

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