Please help me with the above attached question thankyou......
Please help me with the above attached question thankyou......
Abigail Treasa , 6 Years ago
Grade 12
Differential Calculus> Please help me with the above attached qu...
2 Answers
Arun
Last Activity: 6 Years ago
Dear student
Take log to the base e and then differentiate, you will get the required result.
Hope it helps
Allison
Last Activity: 6 Years ago
X^y = e(x-y) = e^x / e^y
X^y * e^y = e^x
(xe)^y = e^x
Take log on both sides of above eq
y * log (xe) = x ---(1)
Differentiate both side wrt x
dy/dx * log x. + ey/xe. = 1
dy/dx. = 1 – y/x
Log(xe)
= x-y / x*log (xe)
From question we know x-y = y * log x
So dy/dx= y*log x
X* Log(xe)
From (1) y*log(xe)=x so y/x=1/log(ex), substitute this is above eq to get answer
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