Differential Calculus
Please answer this small challenging question in the image please.
Please answer this small challenging question in the image please.
1 Answer
Aditya Gupta
This is a very easy question. Put y=x^2
So limit becomes
Lt y tends to zero siny(1-cosy)/y^3
= Lt y tends to zero (1-cosy)/y^2 (as Lt siny/y = 1)
= Lt sin^2y/(y^2(1+cosy))
= 1/(1+1)
=1/2
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