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Differential Calculus> No of values of x where the function atta...

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No of values of x where the function attains its maximum .
Eq in image

Drake , 11 Years ago

Grade 12

1 Answers

Jitender Singh

Ans:
Hello Student,
Please find answer to your question below

$f(x) = cos(x) + cos(\sqrt{2}x)$
Function will always attain maxima at x = zero.
$f'(x) = -sin(x) -\sqrt{2}sin(\sqrt{2}x)$
$f'(x) = -sin(x) -\sqrt{2}sin(\sqrt{2}x) = 0$
$-sin(x) -\sqrt{2}sin(\sqrt{2}x) = 0$
$sin(x) = -\sqrt{2}sin(\sqrt{2}x)$
You can calculate the value of x from here......(1)
$f''(x) = -cos(x) -2cos(\sqrt{2}x)$
Then put the value of x from (1) in here.
If f’’(x) < 0
Thats all the value of x for maxima.
You need to provide interval in which you want to know the number of values.

Last Activity: 11 Years ago

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