Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

no of points of non diffrentibility for f(x) = max{ ||x|-1| , ½ } is 2 5 3

no of points of non diffrentibility for f(x) = max{ ||x|-1| , ½ } is
2
5
3
 

Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
7 years ago
Ans: 5
f(x) = max(||x|-1|, \frac{1}{2}})
f(x) = -x-1, x< -1
= \frac{1}{2}, -1\leq x< \frac{-1}{2}
= x+1, \frac{-1}{2}\leq x< 0
= 1-x, 0\leq x< \frac{1}{2}
= \frac{1}{2}, \frac{1}{2}\leq x< 1
= x-1, x\geq 1
So, there are five points where slope will change. You can easily plot the graph of f(x).
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free