Minimum value of the function f(x) = 1/8 ln x – bx + x^2, x0, b = 0 is for what x?

Question

Minimum value of the function f(x) = 1/8 ln x – bx + x^2, x>0, b >= 0 is for what x?

ANIKET RAJ · Answer

x=(b+√(b^2-1))/4 …............ …................................................................................................................................................................................

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Minimum value of the function f(x) = 1/8 ln x – bx + x^2, x>0, b >= 0 is for what x?

Minimum value of the function f(x) = 1/8 ln x – bx + x^2, x>0, b >= 0 is for what x?

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Minimum value of the function f(x) = 1/8 ln x – bx + x^2, x>0, b >= 0 is for what x?

Minimum value of the function f(x) = 1/8 ln x – bx + x^2, x>0, b >= 0 is for what x?

1 Answers

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Other Related Questions on Differential Calculus

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