Lt (x->0)xcosx – log(1+x)x2how to solve these kind of questions without using expansions

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Differential Calculus> Lt (x->0) xcosx – log(1+x) x 2 how to sol...

Lt (x->0) xcosx – log(1+x)
x²
^{how to solve these kind of questions without using expansions}

seetaram dantu , 8 Years ago

Grade 11

2 Answers

Vikas TU

Last Activity: 8 Years ago

As it is 0/0 indeterminant form solve it by applying L-Hospital 2 times.

Hence,

=> (cosx – xsinx – 1/(1+x))/2x

=> (-sinx – sinx -xcosx + 1/(1+x)^2)/2

Put x = 0

=> ½.

seetaram dantu

Last Activity: 8 Years ago

what if it is not in the form of 0/0?

like cosx- log(1+x)/x²?

if there is an other way too, please let me know

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Differential Calculus> Lt (x->0) xcosx – log(1+x) x 2 how to sol...

Lt (x->0) xcosx – log(1+x) x2how to solve these kind of questions without using expansions

seetaram dantu , 8 Years ago

Vikas TU

seetaram dantu

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Lt (x->0) xcosx – log(1+x)
x²
^{how to solve these kind of questions without using expansions}