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question mark

Lt (x->0) xcosx – log(1+x)
x2
how to solve these kind of questions without using expansions

seetaram dantu , 9 Years ago
Grade 11
anser 2 Answers
Vikas TU
As it is 0/0 indeterminant form solve it by applying L-Hospital 2 times.
Hence, 
=> (cosx – xsinx – 1/(1+x))/2x
=> (-sinx – sinx -xcosx + 1/(1+x)^2)/2
Put x = 0 
=> ½.
Last Activity: 9 Years ago
seetaram dantu
what if it is not in the form of 0/0?
like cosx- log(1+x)/x2?
 
if there is an other way too, please let me know
Last Activity: 9 Years ago
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