Flag Differential Calculus> Log (secx + tan x ) / cos x dx = log ( Se...
question mark

Log (secx + tan x ) / cos x dx = log ( Secy + tan y ) / cos y dy

Navanita Mahanty , 8 Years ago
Grade 12th pass
anser 2 Answers
Arun
if this question is to be proved then,
we know if variable is changed then, no difference is generated. 
Example- integral of f(x) dx= integral of f(y) dy
hence your question is proved
Last Activity: 8 Years ago
Vikas TU
Dear Student,
It can be written as:
log(secx + tanx)dx/cosx = log(secy + tany)dy/cosy
=> secxlog(secx + tanx)dx = secylog(secy + tany)dy
let u = secx. du = log(secx + tanx)dx. Similarly v = = secy. dv = log(secy + tany)dy.
=> udu = vdv.
Integrating both sides, we get u2/2 = v2/2 + c/2.
i.e. sec2x = sec2y + c.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Last Activity: 8 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments