limit x tening to 0 [1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)

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YASWANTH KISHOR · Answer

lim x tends to 0 it is in the form of a m + b m= ab m and then (a m)n = (ab )m then u will get n factorail as answer.

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limit x tening to 0 [1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)

limit x tening to 0
[1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)

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limit x tening to 0 [1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)

limit x tening to 0[1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)

1 Answers

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limit x tening to 0
[1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)