limit[sinx/x] as x tends to 0 where[.] is gif
limit[sinx/x] as x tends to 0 where[.] is gif
udit maniyar , 10 Years ago
Grade 12
Differential Calculus> limit[sinx/x] as x tends to 0 where[.] is...
5 Answers
ng29
Last Activity: 10 Years ago
first of all u must know that
sinx/x
now according to ur question limit[sinx/x] as x tends to 0 will be equal to zero
bcoz gif of any nimber less than 1 will be 0 so value of limit is 0
approve if useful
ng29
Last Activity: 10 Years ago
sinx/x
it was missed in prev answer
ng29
Last Activity: 10 Years ago
sinx/x is less than 1
tanx/x is greater than 1
it was missed in prev answer
grenade
Last Activity: 10 Years ago
the value of lt(x->0)sinx/x is equeal to 1 from the left side this meant that the value might be 0.9999999999999
and [ 0.9999 ] = 0 therefore [sinx/x] =0
Azhar
Last Activity: 5 Years ago
Expand sinx as [(x - x^3/3 +x^5/5 ----------)/x]
Now =>[(1 - x^2/3 +x^4/5 ----------)]
Put lim x->0 =>[1 -0 -0 -----]
So ans = 1
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