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```
lim x tends to infinity [(x^2+5x+3)/(x^2+x+2)]^x=?
lim x tends to infinity [(x^2+5x+3)/(x^2+x+2)]^x=?

```
6 years ago

```							lim x tends to infinity [(x^2+5x+3)/(x^2+x+2)]^x=e^lim x tends to infinity x.[(x^2+5x+3)/(x^2+x+2)-1]=e^lim x tends to infinity x.(4x+1)/(x^2+x+2)=e^lim x tends to infinity 4x^2(1+1/x)/x^2(1+1/x+2/x^2)=e^lim x tends to infinity4(1+1/x)/(1+1/x+2/x^2)applying limit, we gete^4  Ans.Thanks & RegardsRinkoo GuptaAskIITians Faculty
```
6 years ago
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